8150=x^2-19x+50

Solution for 8150=x^2-19x+50 equation:

8150=x^2-19x+50

We move all terms to the left:

8150-(x^2-19x+50)=0

We get rid of parentheses

-x^2+19x-50+8150=0

We add all the numbers together, and all the variables

-1x^2+19x+8100=0

a = -1; b = 19; c = +8100;
Δ = b2-4ac
Δ = 192-4·(-1)·8100
Δ = 32761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32761}=181$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-181}{2*-1}=\frac{-200}{-2}
=+100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+181}{2*-1}=\frac{162}{-2}
=-81
$